A man drags a table 3.95 m across the floor, exerting a constant force of 53.0...

Question

Question

A man drags a table 3.95 m across the floor, exerting a constant force of 53.0 N, directed 34.0° above the horizontal.

(a) Find the work done by the applied force.

(b) How much work is done by friction? Assume the table's velocity is constant.

science physics

Answer 1

Answer #1

here,

s = 3.95 m

constant force , F = 53 N

theta = 34 degree

a)

the work done by the applied force , W = F * s * cos(theta)

W = 53 * 3.95 * cos(34) J

W = - 173.56 J

b)

as the table has constant velocity

the net force on the table is zero

so,the net work done is also zero

so, the work done by friction = - W = - 173.56 J

Answer 2

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