This is from an online game of "Deal or No Deal" that I played.
Question: Find the Expected Value: (Hint: What is the probability of picking any cash value remaining?)
The values are in British currency that I converted to decimals. Not sure if I was supposed to do that.
0.01(1/8) + 1000.00(1/8) + 15000.00(1/8) + 5.00(1/8) + 3000.00(1/8) + 50000.00(1/8) +10.00(1/8) + 5000.00(1/8) = 9251.88
I'm not sure if the question is asking, "What is the probability of picking 1 option out of the 8 available" in which case I would say 1/8. Or, am supposed to find the expected value of the 8 amounts left? Did I use the right formula and get the right answer? Please help. Thank you.
You are supposed to find the expected value of 8 amounts left that is the sum of product of (1/8 * amount left)
>>Note here the probability here is considered uniformly distributed over the value and equals to 1/8.
>> The expected value is required here so your solution is correct
This is from an online game of "Deal or No Deal" that I played. Question: Find...
I am going to play a game of chance, but I want to know if it is worth my while. On average, if I played the game over and over, what amount would I expect to win (+$) or lose (-$) on average per game? That is the mean of the probability distribution that describes the game. It is also call the game's expected value. The formula for expected value is The game I'm playing costs $5 to play. The...
Problem
#5: The derivative is dP/di=[(-182/365)(90000)]/[(1+I(182/365)]^2
where i=11.09%.
dP/di=-40296.81627(-0.002) --> bc of the yield decrease
= 80.593
Problem #6 is where I'm having problems. I'm not sure what it is
asking us to and I don't know how to attempt it. Thanks.
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Hello I would like to ask for some help on this two-part
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Consider the following domain:
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UPDATE: This is all the information I got
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