A fisherman standing in a boat sees a fish on the bottom of a lake with a depth of y2 = 6 m as shown. The fisherman's eyes are y1 = 2 m above the surface of the lake. The index of refraction for the water of the lake is 1.30 and that for air can be taken as 1.00. Note that the ray to the fisherman's eyes from the fish emerges from water at a distance of x1 = 3 m from the fisherman.
1) What is the actual distance, X', to the fish measured along the bottom? X' =
A fisherman standing in a boat sees a fish on the bottom of a lake with...
A fish in a lake sees the Sun set (disappear) earlier than a fisherman in a boat above the fish. What angle above the horizontal does the Sun disappear under the water? (recall: n(water) = 1.33).
A fisherman spies a fish underneath the water, which appears to be at a depth d_0 of 7m. The refraction angle of the light from the fish to the fisherman theta_f is 54 degree. (a) Consider the line perpendicular to the water at the point where the light transitions from water to air. Express the distance l from this line to the fish in terms of theta_f and d_0.- What is its value? (b) Express theta_i, the angle of incidence...
A fisherman sees rays of light apparently diverging from a point
P' on a fish (see figure below). The fish appears to be at y = 1.1
m below the surface. What is its actual depth? (Take ? = 47.1°.)
The answer is not 1.79 m....
(25%) Problem 1: A fisherman spots a fish underneath the water. It appears that the fish is do = 0.33 m under the water surface at an angle of eq = 58 degrees with respect to the normal to the surface of the water. The index of refraction of water is nw = 1.3 and the index of refraction of air is na = 1. Otheexpertta.com A 17% Part (a) The perpendicular distance from the apparent position of the fish...
A person in a boat sees light scattered from a fish in the water (refractive index n=1.33). The light comes up at an angle of 40o relative to the water’s surface. What angle does a line between fish and person make with the water’s surface.
When a fisher casts his line into the water, the location where he sees the fish is not actually where the fish is, due to refracting light. Given that the index of refraction is higher in water than in air, is the horizontal distance to the fish actually farther from the fisher or closer compared to where he sees it?
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.60 s for the boat to travel from its highest point to its lowest, a total distance of 0.600 m . The fisherman sees that the wave crests are spaced 6.00 m apart. Part A How fast are the waves traveling? Part B What is the amplitude of each wave? Part C If the total vertical distance...
(13%) Problem 2: A fisherman spots a fish underneath the water. It appears that the fish is do = 0.81 m under the water surface at an angle of a = 68 degrees with respect to the normal to the surface of the water. The index of refraction of water is n = 1.3 and the index of refraction of air is na = 1. Xdo Otheexpertta.com ► 17% Part (a) The perpendicular distance from the apparent position of the...
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.80 s for the boat to travel from its highest point to its lowest, a total distance of 0.680 m. The fisherman sees that the wave crests are spaced 6.40 m apart. Part A: How fast are the waves traveling? v=_________________m/s Part B: What is the amplitude of each wave? A=__________________m Part C: If the total vertical...
A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.9 s for the boat to travel from its highest point to its lowest, a total distance of 0.60 m. The fisherman sees that the wave crests are spaced 6.6 m apart. A. How fast are the waves traveling? Express your answer in meters per second. B. What is the amplitude of each wave? Express your answer...