1. A flat rectangular plate of dimensions 0.04 x 0.06 m^2 makes an angle of 37 degre with a field electric E = - 600 j N/C. Calculate the electrical flux passing through the plate.
2. Let be a cylindrical rod of radius R and infinitely long carrying a uniform charge and a volume density of ρ. Using Gauss's theorem, show that the modulus of the electric field has a distance r from the cylinder axis is given by E (r) = ρr / (2ε0).
1) Plate area, A= 0.04*0.06 m^2
Electric field, -600j N/C
This, magnitude of the electric field, E= 600 N/C
The angle is 37 degree.
Thus, the electrical flux through the plate,

1. A flat rectangular plate of dimensions 0.04 x 0.06 m^2 makes an angle of 37...
Proof for E (r) = ρr / (2ε0). No calculations. Let be a cylindrical rod of radius R and infinitely long carrying a uniform charge and a volume density of ρ. Using Gauss's theorem, show that the modulus of the electric field has a distance r from the cylinder axis is given by E (r) = ρr / (2ε0).
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2) The number density of conduction electrons in silver is 5.86 x 1028 m-3. independent of temperature. If a cylindrical wire of length L and cross-sectional area A were made of silver its electrical resistance would be given by R= ρ L A where ρ is the resistivity of the material measured in Ω−m. The resistivity can also be shown to be related to microscopic properties of the metal such as the number density of conduction electrons, the mass and...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...