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Assume the standard deviation of security A is .38 and the standard deviation of security B...

Assume the standard deviation of security A is .38 and the standard deviation of security B is .32. The correlation coefficient between A and B is .36. What is the standard deviation of a portfolio composed of 57% security A and 43% security B?
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Answer #2

Solution: Calculating Portfolio Standard Deviation


Formula:

σp=wA2σA2+wB2σB2+2wAwBσAσBρ\sigma_p = \sqrt{w_A^2 \sigma_A^2 + w_B^2 \sigma_B^2 + 2 w_A w_B \sigma_A \sigma_B \rho}


Step 1: Assign Values

  • wA=0.57w_A = 0.57 → weight of security A

  • wB=0.43w_B = 0.43 → weight of security B

  • σA=0.38\sigma_A = 0.38 → standard deviation of security A

  • σB=0.32\sigma_B = 0.32 → standard deviation of security B

  • ρ=0.36\rho = 0.36 → correlation coefficient between A and B


Step 2: Square the Weights and Standard Deviations

wA2=(0.57)2=0.3249w_A^2 = (0.57)^2 = 0.3249
wB2=(0.43)2=0.1849w_B^2 = (0.43)^2 = 0.1849
σA2=(0.38)2=0.1444\sigma_A^2 = (0.38)^2 = 0.1444
σB2=(0.32)2=0.1024\sigma_B^2 = (0.32)^2 = 0.1024


Step 3: Multiply and Add Terms

wA2σA2=0.3249×0.1444=0.04693w_A^2 \sigma_A^2 = 0.3249 \times 0.1444 = 0.04693
wB2σB2=0.1849×0.1024=0.01894w_B^2 \sigma_B^2 = 0.1849 \times 0.1024 = 0.01894
2wAwBσAσBρ=2×0.57×0.43×0.38×0.32×0.36=0.031692 w_A w_B \sigma_A \sigma_B \rho = 2 \times 0.57 \times 0.43 \times 0.38 \times 0.32 \times 0.36 = 0.03169


Step 4: Sum of the Terms

σp2=0.04693+0.01894+0.03169=0.09756\sigma_p^2 = 0.04693 + 0.01894 + 0.03169 = 0.09756


Step 5: Calculate the Standard Deviation

σp=0.097560.2955\sigma_p = \sqrt{0.09756} \approx 0.2955

Final Answer:

The standard deviation of the portfolio is approximately 0.2955 or 29.55%.


answered by: Monu Kumar Gupta
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