Question

A cylindrical aluminum block will be used in this experiment. If the block has a length 4cm, and a diameter 10.4cm, what is its volume in unit of cm3?

Answer 1

here,

radius of cylindrical, r = 10.4/2 = 5.2 cm

L = 4 cm

for the volume of the cylinder

volume of the cylinder = pi * r^2 * L

volume of the cylinder = pi * 5.2^2 * 4

volume of the cylinder = 339.7 cm^3

the volume of the cylinder is 339.7 cm^3

Answer 2

We can use the formula for the volume of a cylinder:

$$\text{Volume}=\pi r^{2}h$$

Where:

• $r$ is the radius of the cylinder.

• $h$ is the height (or length) of the cylinder.

Calculation:

1. Find the radius ($r$):
   The diameter is given as 10.4 cm, so the radius is half of that:

   $$r=\frac{\text{Diameter}}{2}=\frac{10.4\text{cm}}{2}=5.2\text{cm}$$

3. Plug the values into the formula:

   $$\text{Volume}=\pi (5.2\text{cm}{)}^2(4\text{cm})$$

• Length ($h$) = 4 cm

• Radius ($r$) = 5.2 cm

4. Calculate $(5.2\text{cm}{)}^2$:

   $$5.2\times 5.2=27.04{\text{cm}}^2$$

5. Multiply by the length ($h$):

   $$27.04{\text{cm}}^2\times 4\text{cm}=108.16{\text{cm}}^3$$

6. Multiply by $\pi$:
   Using $\pi \approx 3.1416$:

   $$\text{Volume}=3.1416\times 108.16{\text{cm}}^3\approx 339.8{\text{cm}}^3$$

Answer:

The volume of the cylindrical aluminum block is approximately 339.8 cm³.