Question

A 33 N-m torque is applied to a flywheel that rotates about a fixed axis. How much work in joules is done to the flywheel after it has turned through 6 revolutions?

Answer 1

Answer 2

Calculation:

1. Convert revolutions to radians:
   $6\text{ rev}\times 2\pi \text{ rad/rev}=37.7\text{ radians}$$37.7\text{ radians}$.

2. 
   

3. Calculate work using torque and angular displacement:
   $W=\tau \times \theta =33\text{ N-m}\times 37.7\text{ rad}=1244.1\text{ J}$

4. $=$$1244.1\text{ J}$.

Answer:
The work done is 1244.1 joules.