Question

In a gas mixture, the partial pressures are argon 455 mmHg , neon 80 mmHg , and nitrogen 160 mmHg .What is the total pressure (atm) exerted by the gas mixture?

Answer 1

Calculation:

1. Add the partial pressures:
       Argon (455 mmHg) + Neon (80 mmHg) + Nitrogen (160 mmHg)

2.       = 695 mmHg.

3. 
   

4. Convert mmHg to atm:
   Since 1 atm = 760 mmHg, divide the total pressure by 760:
   $\frac{695\text{ mmHg}}{760\text{ mmHg/atm}}=0.91\text{ atm}$$0.91\text{ atm}$.

5. 
   

So, the total pressure is 0.91 atm

Answer:
                The total pressure exerted by the gas mixture is 0.91 atm.

Answer 2