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Arrange the following in decreasing order of standard entropy: K(s), KCl(s), KCl(aq) EXPLAIN WORK!

Arrange the following in decreasing order of standard entropy: K(s), KCl(s), KCl(aq) EXPLAIN WORK!

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Answer #1

Second one is in aqueous phase and first one is in solids phase.

So randomness of second will be more than the first one. And entropy is the measure of randomness .so entropy of KCl(aq) will be more than that of KCl(s)

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