Question

A 4.66 L sample of gas is warmed from 273 K to a final temperature of 398 K. Assuming no change in pressure, what is the final volume of the gas?

Answer 1

Given:

• Initial volume ($V_1$) = 4.66 L

• Initial temperature ($T_1$) = 273 K

• Final temperature ($T_2$) = 398 K

• Pressure constant

Formula (Charles's Law):

$$\frac{V_1}{T_1}=\frac{V_2}{T_2}$$

Solve for final volume ($V_2$):

$$V_2=V_1\times \frac{T_2}{T_1}=4.66\text{L}\times \frac{398\text{K}}{273\text{K}}$$

Calculation:

$$V_2=4.66\times 1.4578\approx 6.79\text{L}$$

Answer:
The final volume is 6.79 L.