Question

Bilirubin (mw= 584) the major constituent of pile is measured to detect liver disease and to monitor transfusion in Rh factor cases. How much bilirubin is required to make 100ml of (a) 0,1 mg/dL and (b) 0.9 mg/dL solution as standards?

Answer 1

Answer 2

Given:

• Molecular weight (mw) of bilirubin = 584 (not directly needed for this calculation)

• Desired concentrations:

• (a) 0.1 mg/dL

• (b) 0.9 mg/dL

• Final volume = 100 mL

• 
  

Conversion Notes:

• 1 dL = 100 mL

• Therefore, the desired concentration in mg/100 mL is numerically the same as mg/dL.

• 
  

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(a) For 0.1 mg/dL solution:

1. Desired concentration: 0.1 mg in 100 mL (0.1 mg/dL).

2. Amount needed for 100 mL:

• Since 0.1 mg is required per 100 mL, no further calculation is needed for the given volume.

• 
  

• Answer: 0.1 mg of bilirubin is required to make 100 mL of a 0.1 mg/dL solution.

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(b) For 0.9 mg/dL solution:

1. Desired concentration: 0.9 mg in 100 mL (0.9 mg/dL).

2. 
   

3. Amount needed for 100 mL:

• Since 0.9 mg is required per 100 mL, no further calculation is needed for the given volume.

• Answer: 0.9 mg of bilirubin is required to make 100 mL of a 0.9 mg/dL solution.