Using the multinomial formula, find the probability of the following data. Frequency Probability 2 0.38 3 0.45 1 0.17 Group of answer choices 0.728 0.134 0.013 0.325.
from multinomial distribution:
probability of given event =(6!/(3!*2!*1!)*(0.38)^2*(0.45)^3*(0.17)^1 =0.134
Using the multinomial formula, find the probability of the following data. Frequency Probability 2 0.38 3...
Using the multinomial formula or MULTI program, find the probability of the following data. Probability 1/6 1/3 3/8 1/8 Frequency 4 2 3 1 Group of answer choices 0.007121 0.0224 0.001432 0.0658.
20) Use the multinomial formula and find the probability for the following data. n=6, X1 = 3, X = 2, X3 = 1, P1 = 0.58, P2 = 0.25, P3 = 0.17 A) 0.072 B) 0.124 C) 0.002 D) 0.012
QUESTION 26 Using the Binomial Probability formula below, find PCX)when n 10, X -7,p 0.45, and q 0.55. n! O A. .0746 O B..0080 O C..0037 O D..1665 QUESTION 27 using the Binomial Probability table, find P(X) when n # 17, X# 10, and p-0.3 ○ A. 0.1 20 O B. 0.013 ° C. 0.009 ○ D. 0.225
Using the following table, use the compliment rule to find the classical probability of selecting an employee in either grades C, D, E, or F or a Female from this group. What formula would you use for this? Gender\Grade level: A B C D E F Total Females 12 4 2 3 2 2 25 Males 3 3 3 2 10 4 25 Total: 15 7 5 5 12 6 50 Group of answer choices 1- 6/50 1- 53/50 1-...
A test of goodness-of-fit for a multinomial distribution where Ho: p1=.2, p2=.5, p3=.3 results in a the x2 statistic equals 6.7, at a=.05 you should conclude: Group of answer choices A. The sample is uniformly distributed. B. The sample is normally distributed. C. There is no evidence against the hypothesized multinomial distribution. D. There is evidence that the sample does not come from the hypothesized multinomial distribution.
Test the following hypotheses for a multinomial probability distribution by using the x^2 goodness of fit test. Ho:Pa=0.2, Pb=0.4, Pc=0.4 Ha: The probabilities are not : Pa=0.2, Pb=0.4, Pc=0.4 A sample of size 200 yielded 50in category A, 110 in category B, and 40 in category C. Use a=0.01 and test to see whether the probabilities are as stated in Ho. A: use the p-value approach. x^2= P value: Conclusion: b. Repeat the test using the critical value approach x2.01=...
Refer to the frequency distribution and find the standard deviation by using the formula Blood Platelet Count of Males (1000 cells/uL) Frequency 0-99 100-199 200-299 300-399 400-499 500-599 600-699 3 (f-x) where x n(n-1) 82 21 0 represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Compare this value with the standard deviation found using the original list of data values, 67.7
A multinomial experiment with k- 4 cells and associated cell counts produced the data shown in the following table. Category 1 Category 2 Category 3 Category 4 62 |42 |37 Test the following hypothesis: Ho: pi-P2 = P3 = p4 , HA: At least one of the proportions exceeds 1/4. Calculate the Chi-Squared,x2 test statistic. Round your answer to 2 decimal places A multinomial experiment with k = 4 cells and associated cell counts produced the data shown in the...
3. A multinomial experiment with k-4 cells and n=201 produced the data shown in the one-way table to the right. Complete parts a through e. CELL 1 CELL 2 CELL 3 CELL 4 60 Do these data provide sufficient evidence to conclude that the multinomial probabilities differ? Test using alpha=0.10. What is the null and alternative hypothesis? II. Calculate the test statistic. (6) III. Calculate the p-value. IV. What is your conclusion?
Using historical records, a manufacturing firm has developed the following probability distribution for the number of days required to get components from its suppliers. The distribution is shown here, where the random variable x is the number of days. Х P(x) 4 0.17 5 0.38 6 0.31 7 0.105 8 0.035 Using historical records, a manufacturing firm has developed the following probability distribution for the number of days required to get components from its suppliers. The distribution is shown here,...