Using Fe2O3+3CO = 3CO2+2Fe, tell how many grams or iron would be produced if 454 grams of iron(III) oxide reacts completely. How many grams or CO are needed to react with this much iron (III) oxide?
Chemical reaction;
Fe2O3 + 3CO ---------> 3CO2 + 2Fe
Molar mass of Fe2O3 = 160g/mol
Molar mass of Fe = 56g/mol
Molar mass of CO = 28g/mol
1 mole (160g) Fe2O3 gives = 2 moles Fe ( 2×56g/mol)
Then 454g Fe2O3 will produce = (112g-Fe/160g-Fe2O3)×454g-Fe2O3 = 317.8 g Iron will produce.
For 1 mole Fe2O3 (160g) it requires = 3 moles CO (3×28g/mol)
Then for 454g Fe2O3 , it will require = (84g-CO/160g-Fe2O3)×454g-Fe2O3 = 238.35 g CO is needed .
Using Fe2O3+3CO = 3CO2+2Fe, tell how many grams or iron would be produced if 454 grams...
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