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A 88 kg runner taking part in a 200 m dash must run around the end...

A 88 kg runner taking part in a 200 m dash must run around the end of a track that has a circular arc with a radius of curvature of 25 meters. if he completes the 200 m dash in 27.45 s and runs at constant speed throughout the race, what is the magnitude of his centripetal force as he runs the curved portion of the track?

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Answer #1

Here Velocity of the runner v = distance/time = 200m/27.47s = 7.28 m/s

Centripetal force F = mv^2/r where m is mass and r is radius of curvature

= 88kg*(7.28m/s)^2/25m

= 186.55 N answer

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