You are on a mysterious planet and notice that a 2.1 m long simple pendulum has a period of 6.5 s when its angular amplitude is 6° or less.
A.) Determine the value for g (the free fall acceleration) on the surface of this planet.
B.) If you HALVED the length of the pendulum, what would its period be?
Part B; You are on Earth and notice that the pendulum in
grandfather clock is 0.24 m long. Determine the following if its
angular amplitude is 3.4°.
ω =
f =
T =
A =
vmax =
amax =
You are on a mysterious planet and notice that a 2.1 m long simple pendulum has...
Part 1: Pendulum on allen planet You are on a mysterious planet and notice that a 2.7 m long simple pendulum has a period of 3s when its angular amplitude is " or less. A) Determine the value for the free fall acceleration on the surface of this planet. B.) If you DOUBLED the length of the pendulum, what would its period be? Part 2: Pendulum on Earth You are on Earth and notice that the pendulum in grandfather clock...
You are on Earth and notice that the pendulum in
grandfather clock is 1.27 m long. Determine the following if its
angular amplitude is 3.7°.
Part 2: Pendulum on Earth You are on Earth and notice that the pendulum in grandfather clock is 1.27 m long. Determine the following if its angular amplitude is 3.7° W = 2.77 rad/s f 4411 Hz T 2.267 s A .0052 m X = .0144 m/s X Vmax amax .0398 m/s^2 X Submit Answer
You are on Earth and notice that the pendulum in grandfather clock is 0.89 m long. Determine the following if its angular amplitude is 4.6° W = 3.32 rad/s f 0.528 hz T 1.893 sec A = 0.0715 m = 0.237 m/s Vmax 0.788 m/s^2 amax =
please help me answers all part of question 11
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11. 1.25/10 points Previous Answers SHM: Pendulum 1/6 Submissions Used e Content My Notes A Part 1: Pendulum on allen planet You are on a mysterious planet and notice that a 2.7 m long simple pendulum has a period of 3s when its angular amplitude is for less A) Determine the value for 3.7974 m/s the free full acceleration on the surface of this planet .) If you DOUBLED the...
The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity on this planet if the length of the pendulum is 1.00 m.
Consider a simple pendulum that is 1.05 m long. It swings (oscillates) on a planet where gravity is 1/3 the value of gravity on the Earth. What is the pendulum's period of oscillation?
Consider a simple pendulum that is 1.15 m long. It swings (oscillates) on a planet where gravity is 1/3 the value of gravity on the Earth. What is the pendulum's period of oscillation?
A simple pendulum on the surface of the Earth has period T. On a different planet, the same pendulum has period 27. The free-fall acceleration on this planet is 04g O g/4 O2g O g/2
ans: 12.8 m/s^2
You crash land your spaceship on a mysterious planet. You want to figure out g, the acceleration due to gravity, on the surface of the planet. Fortunately, you brought a stopwatch and simple pendulum: a 75.0 centimeter long string tied to a 1.50 kg mass. You measure the period of the pendulum to be 1.52 seconds. What is the value of g, in units of m/s2? Assume there is no air resistance as the pendulum swings.
1. How much is the period of 1=1.00 m long pendulum on the Moon (g = 1.600 m/s2) 4.97 sec. 2. On a planet X pendulum of the length 0.500 m makes 50.0 oscillations in 1.00 min. Find the acceleration of gravity on the planet X. g = 13.7 m/s2. 3. Find the period of small oscillations of a meter stick suspended by its end near Earth surface (assume g=9.800 m/s2). Notice that this is not a simple pendulum but...