Balance the following in basic solution. (Omit states-of-matter from your answer. Use the lowest possible whole number coefficients.)
(a) Sc(s) + CrO42−(aq) → Sc(OH)3(s) + Cr(OH)4−(aq)
Oxidation reaction
Reduction reaction
Net reaction
(b) NO2−(aq) + H2(g) → N2O(g)
Oxidation reaction
Reduction reaction
Net reaction
(c) ClO3−(aq) + Cu(OH)2(s) → ClO4−(aq) + CuOH(s)
Oxidation reaction
Reduction reaction
Net reaction
(d) Sn(OH)2(s) + O2(g) → SnO2(s)
Oxidation reaction
Reduction reaction
Net reaction
Balance the following in basic solution. (Omit states-of-matter from your answer. Use the lowest possible whole...
Balance the following in acidic solution. (Omit states-of-matter from your answer. Use the lowest possible whole number coefficients.) (a) H2O2 + Mn2+ ? H2O + Mn4+ Oxidation reaction: Reduction reaction: Net reaction: (b) Al + Cr2O72? ? Al3+ + Cr3+ Oxidation reaction: Reduction reaction: Net reaction: (c) Hg + PbO2 ? Hg22+ + Pb2+ Oxidation reaction: Reduction reaction: Net reaction:
2. Balance the following chemical reaction in basic conditions using the lowest possible whole number coefficients. (Enter coefficients for one and zero- blanks will be marked incorrect.) Unbalanced Reaction: ClO4−(aq) + Ni(OH)2(s) → ClO3−(aq) + NiO2(s) Balanced Reaction: ClO4−(aq) + Ni(OH)2(s) + H2O(l) + OH−(aq) + H+(aq) → ClO3−(aq) + NiO2(s) + H2O(l) + OH−(aq) + H+(aq) Incorrect. Tries 1/13 Previous Tries
Balance the following equations. (Use the lowest possible
whole-number coefficients. These may be zero.)
(a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq)
MnO4- + Cl-
+ H+ + H2O Mn2+
+ Cl2 + H+
+ H2O
(b) Cr2O72-(aq) +
NO2-(aq) Cr3+(aq) +
NO3-(aq)
Cr2O72-
+ NO2- + H+
+ H2O Cr3+
+ NO3- + H+
+ H2O
(c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g)
Tl2O3 + NH2OH
+ OH- + H2O TlOH(s) + N2
+ OH- + H2O
(d) CrO42-(aq) +
C2O42-(aq) Cr(OH)3(s) +
CO2(g)
CrO42-
+ C2O42-
+ OH- + H2O Cr(OH)3
+ CO2 + OH-
+ H2O
(1) Balance the following oxidation–reduction reaction by the half-reaction method. (Use the lowest possible coefficients for the reaction.) CuCl2 (aq) + Zn (s) = Cu (s) + ZnCl2 (aq) (2) Balance the following oxidation–reduction reaction by the half-reaction method. (Use the lowest possible coefficients for the reaction.) H2 (g) + Ag+ (aq) = Ag (s) + H+ (aq)
References] Balance each of the following oxidation-reduction reactions by using the oxidation states method. (Use the lowest possible coefficients for all reactions.) Cl2(g)+Ga(s)- Ga3 (aq) CI (aq) a. Ga3 (aq)+ CI (aq) Cl2(9) + Ga(s) O2(9)+ H2O(1)+Sn(s)Sn(OH)2(s) b. H2O (1) + O2(9) + Sn(OH)2 (s) Sn(s) H* (aq)MnO4(aq) +Cr2 (aq ) -Mn2 (aq) +Cr3+ (aq) +H2O(l) с. Cr (aq) H (aq) + MnO4 (aq) + Cr (aq) + Mn2+ (aq) + Н. О(1) 6 item attempts remaining Submit Answer Try...
Balance the following equations. (Use the lowest possible whole number coefficients. Include states of matter under the given conditie (a) Cas(PO )2(aq) + H,PO, (aq) + Ca(H,PO)2(aq) chemPad Help X. Xº - Greek (b) ICI,(s) + H2O(g) + 1r02(s) + HCl(g) chemPad Help X.X" e Creek (c) Fe(s) + H2001) -- 70,0 (5) + H2(g) chemPad Help Greek -
Balance the redox reactions: basic: ClO-(aq)+Cr(OH)4-(aq)----> CrO42-(aq)+Cl-(aq) MnO4-(aq)+Br-(aq)--> MnO2(s)+BrO3-(aq) NO2-(aq)+Al(s)--->NH3(g)+AlO2- Aidic: ClO4-(aq)+Cr(OH)4---->ClO3-(aq)+Cl2(g)
When the following oxidation–reduction reaction in basic solution is balanced, what is the lowest whole-number coefficient for OH–, and on which side of the balanced equation should it appear? Cr2O3(s) → Cr(OH)2(aq) + CrO42–(aq) a. 2, reactant side b. 10, product side c. 4, product side d. 4, reactant side e. 2, product side The answer is a, but I dont know how to get to the answer.
Balance the following oxidation-reduction equations. The reactions occur in acidic solution. (Use the lowest possible coefficients. Omit states of matter. Add H20 or H to any side of the reaction if it is needed.) a. Pb + Bi0,- + PbO2+ BiS+ Pb + BiO3 + PbO2 + Bi9+ + b. Cr,0,? + Fe2+ + Cr+ + Fe3+ | Cr₂O₂ ² + | Fe²+ + + Fel- c. MnO, +1“ + Mn2+ + Cl2 MnO2 + Cl + Mn + Cl2...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq) + NO2 (aq) = Cr3+ (aq) + NO3"(aq) Cr20,2- + NO3 + H+ + H2O= Cr3+ + NO3 + H+ + H20 (b) Mn04 (aq) + CH3OH(aq) Æ Mn2+ (aq) + HCO2H(aq) MnO4 + CH3OH + H+ + H2O= Mn2+ + HCO2H + H+ + H2O (c) ClO2(aq) + H2O2(aq) = C102 (aq) + O2(9) C102 + H2O2 + OH + H20 = ClO2...