An economist reports that 182 of a random sample of 400 middle-income Americans actively participate in...
An economist reports that 182 of a random sample of 400 middle-income Americans actively participate in the stock market.
Formulate the 95% confidence interval for the proportion of middle-income Americans who actively participate in the stock market.
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x = (y)(z). That is, what is x?y?z?
Homework Answers
The 95% confidence interval of the
proportion of middle-income Americans who actively participate in
the stock market = [
,
], where, 
= 182/400 = 0.455, n = 400
Thus, 95% C.I. = [0.455 - 0.0488, 0.455 + 0.0488] = [0.4062, 0.5038] (Ans).
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