Calculate the length in angstroms of a 100-residue segment of the α keratin coiled coil.

Question

Question

science chemistry

Answer 1

Answer #1

For keratin,

1 -helical turn = 3.6 residues = 5.1 Angstrom

So, 3.6 residues correspond to a length of 5.1 Angstrom

Therefore, 100 residues correspond to a length of = (5.1 x 100)/3.6 = 142 Angstrom

Therefore, the length of a 100-residue segment of the α keratin coiled coil = 142 Angstrom

Answer 2

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