The coefficient of static friction between a sled and the snow is .15, with the coefficient of kinetic friction of .13. A 275N boy sits on the 200 N sled. How much force directed parallel to the horizontal surface is required to start the sled in motion? How much force is required to keep the sled in motion?
Total weight of boy and sled = 275 + 200 = 475 N
This is the weight which is equal to the Normal force on the
combined system
Force required to start motion = µs N = µs
* 475 = 0.15 * 475 N = 71.25 N
Force required to keep the sled in motion =μk N
= μk * 475 = 0.13 * 475 N = 61.75 N
The coefficient of static friction between a sled and the snow is .15, with the coefficient...
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