For conformation of cyclohexane why would some of the energies in kj/mol be the same? For example: at a dihedral angle of 0 degrees celsius and 360 they have the same energy value of about 63 kj/mol.
Because the conformation with dihedral angle 0 0 and 360 0 are same. The orientation of the groups in the cyclohexane in these two conformations are exactly same. Hence the bond energies and the steric strain in these two conformations are exactly same that leads to the same energies of the conformations.
For conformation of cyclohexane why would some of the energies in kj/mol be the same? For...
The anti conformation of 1, 2-dichloroethane, Cl-CH_2-CH_2- Cl, is 4.81 kJ mol^-1 (1.15 kcal mol^-1) more stable than the gauche conformation. The two energy barriers (measured relative to the energy of the gauche conformation) for carbon-carbon bond rotation are 21.5 kJ mol^-1 (5.15 kcal mol^-1) and 38.9 kJ mol^-1(9.3 kcal mol^-1). Sketch a graph of potential energy versus dihedral angle about the carbon-carbon bond. Show the energy differences on your graph and label each minimum and maximum with the appropriate...
Table 9.3: Average Bond Energies Bond Energy (kj/mol) Bonic Energy Il/mol) Bond Energy (kJ/mol) Bond Hond H-H 438 N- N 103 NON 418 210 GHz + 50; Propane Oxygen gas 300, + 4H20 Carbon Water dioxide Bond BF Br-CI BB I- 1-Br 484 N-O 200 368 9:46 222 590 272 200 545 NAF NCI N- Br 151 323 431 364 Do your calculations here: 297 159 301 347 142 206 611 0-0 0-0 498 308 623 190 SO OF 0-...
Use the table to answer questions about bond energies. Bond Bond Energy (KJ/mol) C—C 347 C=C 611 C-H 414 C-O 360 C=O 736 O-O 142 O=O 498 H-O 464 (i) Calculate the bond energy for breaking all the bonds in a mole of methane, CH4 Express your answer numerically in kilojoules per mole. Change in Heat Ch4 ?=KJ/mol (ii) Calculate the bond energy for breaking all the bonds in a mole of O2 molecules? Express your answer numerically in kilojoules...
A: The activation energy of a certain reaction is 36.8 kJ/mol . At 27 ∘C , the rate constant is 0.0120s−1. At what temperature in degrees Celsius would this reaction go twice as fast? B: Given that the initial rate constant is 0.0120s−1 at an initial temperature of 27 ∘C , what would the rate constant be at a temperature of 100. ∘C for the same reaction described in Part A?
The activation energy of a certain reaction is 33.6 kJ/mol . At 23 ∘C , the rate constant is 0.0150s−1. At what temperature in degrees Celsius would this reaction go twice as fast? Given that the initial rate constant is 0.0150s−1 at an initial temperature of 23 ∘C , what would the rate constant be at a temperature of 120. ∘C for the same reaction described in Part A?
Question Three (6 marks) The average bond energies (in kJ mol) are given in the table below. ?-? 351 | ?-? 610 0-0 152 | ?-? 496 | C-0365 | ?-? 740 | 0-11460 | ??? 840 | H-H 436 | CHI 413 1. Explain why bond energy values are always positive. Place the three bonds, C-H, H-Hand O-H, in the order of increasing bond length (shortest first) 2. 3. Calculate the enthalpy change of the reaction below using the...
Part A The activation energy of a certain reaction is 34.9 kJ/mol . At 23 ∘C , the rate constant is 0.0110s−1. At what temperature in degrees Celsius would this reaction go twice as fast? Part B Given that the initial rate constant is 0.0110s−1 at an initial temperature of 23 ∘C , what would the rate constant be at a temperature of 120. ∘C for the same reaction described in Part A?
Part A: The activation energy of a certain reaction is 44.9 kJ/mol. At 25 ∘C, the rate constant is 0.0120s−1. At what temperature in degrees Celsius would this reaction go twice as fast? Part B: Given that the initial rate constant is 0.0120s−1 at an initial temperature of 25 ∘C, what would the rate constant be at a temperature of 120. ∘C for the same reaction described in Part A?
please explain why
3. The first six ionization energies (kJ/mol) of a certain SECOND-ROW element are as follows: Ij = 1,086 12 = 2350 13 = 4620 14 = 6220 Is = 38,000 16 = 47,261 The most likely identity of this element is a) B b) 0 c) N d) Be e) C
Part A) The activation energy of a certain reaction is 33.9 kJ/mol . At 20 ∘ C , the rate constant is 0.0160 s −1 . At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Answer was: T 2 = 35 ∘ C Part B Given that the initial rate constant is 0.0160 s −1 at an initial temperature of 20 ∘ C , what would the rate constant...