3. Let’s now consider a slightly different reaction, a reaction in solution:
Glucose (aq)--->Fructose (aq)
a). Give the expression of the equilibrium constant K in terms of the concentration of glucose and fructose in the solution. What kind of reference states do you assume for the two solutes here?
b). If someone determined that this conversion has ∆rG0=+1.7kJmol-1 in aqueous solution. If you start off with a solution of 0.1M of pure glucose in the solution, what would be final concentration of glucose and fructose respectively assuming the two can interconvert and reach equilibrium.
d) In reality, do you think glucose will be converted to fructose in water? What prevents the conversion? You may look up google to learn more about structural difference between glucose and fructose.
4.Consider the reaction CO(g) + H2O (g) <---> CO2(g) + H2(g) , K = 0.0611 at 2000K. A reaction mixture initially contains CO(g) partial pressure of 1344torr and H2O partial pressure 1760torr and 2000K. Calculate the equilibrium partial pressures of each of the products after the reaction reaches equilibrium (you may use “simplifying approximations” in solving the equation).
a) K= [Concentraion of Fructose/[Concentraion of Glucose]
b)c) Since the gibbs free energy
is positive this reaction is not feasible. In real life catalyst
such as lithium or certain enzymes are used to catalyze this
reaction.
3. Let’s now consider a slightly different reaction, a reaction in solution: Glucose (aq)--->Fructose (aq) a)....
Consider the following reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g) Kp=0.0611 at 2000 K A reaction mixture initially contains a CO partial pressure of 1346 torr and a H2O partial pressure of 1762 torr at 2000 K. A.) Calculate the equilibrium partial pressure of CO2. B.) Calculate the equilibrium partial pressure of H2.
Consider the following reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g) Kp=0.0611 at 2000 K A reaction mixture initially contains a CO partial pressure of 1380 torr and a H2O partial pressure of 1770 torr at 2000 K. Calculate the equilibrium partial pressure of CO2.
Consider the following reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g) Kp=0.0611 at 2000 K -A reaction mixture initially contains a CO partial pressure of 1310 torr and a H2O partial pressure of 1790 torr at 2000 K. - Calculate the equilibrium partial pressure of CO2. (Express the pressure in torr to three significant figures.)
Consider the following reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g) Kp=0.0611 at 2000 K A reaction mixture initially contains a CO partial pressure of 1390 torr and a H2O partial pressure of 1750 torr at 2000 K. Calculate the equilibrium partial pressure of CO2 and H2. Express the pressure in torr to three significant figures.
Consider the following reaction: CO(g) + H2O(g)CO2(g) + H2 (9) Kp-0.0611 at 2000 K A reaction mixture initially contains a CO partial pressure of 1342 torr and a H2 O partial pressure of 1778 torr at 2000 K. Calculate the equilibrium partial pressure of CO2
1. Calculate the equilibrium partial pressure of CO2.
2. Calculate the equilibrium partial pressure of H2.
Consider the following reaction: CO(g) + H2O(g) = CO2(g) + H2(g) K = 0.0611 at 2000 K A reaction mixture initially contains a CO partial pressure of 1360 torr and a H2O partial pressure of 1770 torr at 2000 K.
Consider the following reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g)CO(g)+H2O(g)⇌CO2(g)+H2(g) Kp=0.0611Kp=0.0611 at 2000 KK A reaction mixture initially contains a COCO partial pressure of 1354 torrtorr and a H2OH2O partial pressure of 1756 torrtorr at 2000 KK. A) Calculate the equilibrium partial pressure of CO2CO2 . B) Calculate the equilibrium partial pressure of H2H2.
Consider the following reactionCO(g)+H2O(g) ⇌ CO2(g)+H2(g) Kp=0.0611 at 2000 KA reaction mixture initially contains a CO partial pressure of 1390 torr and a H2O partial pressure of 1730 torr at 2000 K.You may want to reference (Pages 656-664) Section 15.8 while completing this problemPart BCalculate the equilibrium partial pressure of H2.
1. For the reaction 2A(g)⇌B(g)+2C(g), a reaction vessel initially contains only A at a pressure of PA=265 mmHg. At equilibrium, PA=41 mmHg. Calculate the value of Kp. (Assume no changes in volume or temperature.) 2. consider the following reaction: A(g)⇌2B(g) Find the equilibrium partial pressures of A and B for each of the following different values of Kp. Assume that the initial partial pressure of B in each case is 1.0 atm and that the initial partial pressure of A...
Consider the reaction: CO(g)+H2O(g)⇌CO2(g)+H2(g) K=0.118 at 4000 K A reaction mixture initially contains a CO partial pressure of 1361 mbar and a H2O partial pressure of 1781 mbar at 4000 K. Calculate the equilibrium partial pressure of CO Calculate the equilibrium partial pressure of H2O Calculate the equilibrium partial pressure of CO2 Calculate the equilibrium partial pressure of H2