A multiple regression analysis produced the following tables.
Coefficients |
Standard Error |
t Statistic |
p-value |
|
Intercept |
1411.876 |
762.1533 |
1.852483 |
0.074919 |
x1 |
35.18215 |
96.8433 |
0.363289 |
0.719218 |
x12 |
7.721648 |
3.007943 |
2.567086 |
0.016115 |
df |
SS |
MS |
F |
|
Regression |
2 |
58567032 |
29283516 |
57.34861 |
Residual |
25 |
12765573 |
510622.9 |
|
Total |
27 |
71332605 |
The regression equation for this analysis is ____________.
Select one:
A. y = 762.1533 + 96.8433 x1 + 3.007943 x12
B. y = 1411.876 + 762.1533 x1 + 1.852483 x12
C. y = 1411.876 + 35.18215 x1 + 7.721648 x12
D. y = 762.1533 + 1.852483 x1 + 0.074919 x12
E. y = 762.1533 - 1.852483 x1 + 0.074919 x12
A multiple regression analysis produced the following tables. Coefficients Standard Error t Statistic p-value Intercept 1411.876...
A multiple regression analysis produced the following tables. Coefficients Standard Error t Statistic p-value Intercept 1411.876 35.18215 7.721648 762.1533 96.8433 3.007943 1.852483 0.074919 0.363289 0.719218 2.567086 0.016115 2 df Regression 2 Residual 25 27 58567032 12765573 71332605 MS 29283516 57.34861 510622.9 Total Using a-0.10 to test the null hypothesis Ho: b2 0, the critical t value is. ± 1.316 ± 1.314 ± 1.703 ± 1.780 ± 1.708
A multiple regression analysis produced the following tables: Predictor Intercept xi x2 Coefficients 624.5369 8.569122 4.736515 Standard Error 78.49712 1.652255 0.699194 t statistic 7.956176 5.186319 6.774248 p value 6.88E-06 0.000301 3.06E-05 Source Regression Residual Total df 2 11 13 SS 1660914 156637.5 1817552 MS 830457.1 14239.77 F 58.31956 p value 1.4E-06 For x1= 30 and x2 = 100, the predicted value of y is 753.77 O 1,173.00 O 1,355.26 615.13 6153.13
A multiple regression analysis produced the following
tables:
Predictor Intercept Xi x2 Coefficients 616.6849 -3.33833 1.780075 Standard Error 154.5534 2.333548 0.335605 t statistic 3.990108 -1.43058 5.30407 p value 0.000947 0.170675 5.83E-05 Source Regression Residual Total df 2 15 17 SS 121783 61876.68 183659.6 MS 60891.48 4125.112 p value 0.000286 F 14.76117 Using a = 0.01 to test the null hypothesis Ho: B1 = B2 = 0, the critical F value is 8.68 6.36 8.40 O 6.11 O 3.36
What is the coefficient?
What is the standard error?
What is the z-statistic?
Is the coefficient sufficiently different from zero? How about
one? Explain.
SUMMARY OUTPUT Regression Statistics Multiple R 0.58175248 R Square 0.33843594 Adjusted R S 0.31393357 Standard Err 1.1991813 Observations 29 ANOVA df SS MS Significance F 0.000932269 Regression 1 19.86268888 19.86268888 13.8123745 Residual 38.82696629 27 1.438035789 Total 58.68965517 28 Coefficients Standard Error P-value t Stat Lower 95% Upper 95% Lower 95.0% Upper 95.0% Intercept -0.0202247 0.223805467 -0.090367404...
1st regression analysis
2nd regression analysis
1. Analyze the two regression analysis's above and make
a recommendation on if the organization should increase, decrease,
or retain their pricing and why?
2. What happens to the dependent variable Y if the price
X1 decreases in the second regression analysis?
SUMMARY OUTPUT Y=UNITS SOLD X=PRICE Regression Statistics Multiple R R Square Adiusted R S Standard Error Observations 0.874493978 0.764739718 0.756026374 159.2178137 29 quare ANOVA df MS Significance F 1 2224908.261 2224908.26187.76650338 5.64792E-10...
You were asked by your manager to evaluate the regression tables below to decide which cost driver would be best to use for the production department. Since your manager is new and does not understand the regression analysis tables, you will need to explain why one set of statistics is better than the other and why you have chosen the better driver. Manufacturing Direct Labor Hours Regression Statistics Multiple R 0.799304258 R Square 0.638887297 Adjusted R Square 0.602776026 Standard Error...
7,10,11
Based on the following regression output, what is the equation of the regression line? Regression Statistics Multiple R 0.917214 R Square 0.841282 Adjusted R Square 0.821442 Standard Error 9.385572 Observations 10 ANOVA df SS MS Significance F 1 Regression 3735.3060 3735.30600 42.40379 0.000186 8 Residual 704.7117 88.08896 9 Total 4440.0170 Coefficients Standard Error t Stat P-value Lower 95% Intercept 31.623780 10.442970 3.028236 0.016353 7.542233 X Variable 1.131661 0.173786 6.511819 0.000186 0.730910 o a. 9; = 7.542233+0.7309 Xli o b....
only part II is needed
Regardless of your answer to (a), you come up with the following multiple regression model. b. Coefficients: Estimate Std. Error t value Pr>lt (Intercept) 72.2285 1.2697 56.89 2e-16 X2 X3 Residual standard error: 7.25 on 191 degrees of freedom Multiple R-squared: 0.494, Adjusted R-squared: 0.489 F-statistic: 93.3 on 2 and 191 DF, p-value: <2e-16 0.4590 0.0524-8.76 1.1e-15 0.4146 0.1290 3.21 0.0015** I) What percentage of the total variation in Life Expectancy can you explain with...
The following is a partial result of Multiple Regression analysis conducted in Excel. Predictor Coefficients Standard Error t Statistic p-value Intercept -139.61 2548.99 -0.05 0.157154 x1 4.25 22.25 1.08 0.005682 x2 3.10 17.45 1.87 0.03869 x3 15.18 11.88 1.03 0.00002 Specify the following: Regression Equation: Which independent/predictor variables are statistically significant at α = 0.01 and Why?
Based on the below data what will be the value of multiple R? Regression Statistics Multiple R R Square Adjusted R Square Standard Error Observations 8 ANOVA df SS MS F Regression 1 29 29 7 Residual 6 26 4 Total 7 Coefficients Standard Error t Stat P-value Intercept 1 31.274666 3.984284 0.007248 Advertising (thousands of S) 42 6.19330674 1.610802 0.158349 Submit Answer format: Number Round to: 2 decimal places.