Question

An ionized oxygen molecule (O2^+) at point A has charge +e and moves at 1.68 ✕...

An ionized oxygen molecule (O2^+) at point A has charge +e and moves at 1.68 ✕ 10^3 m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop at point B, a distance of 0.811 mm past A on the x-axis. Calculate the x-component of the electric field and the potential difference between points A and B. (The mass of an oxygen molecule is 5.31 ✕ 10^−26 kg and the fundamental charge is e = 1.60 ✕ 10^−19 C.)

(a) the x-component of the electric field (in V/m)

V/m

(b) the potential difference between points A and B (in V)

V

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
An ionized oxygen molecule (O2^+) at point A has charge +e and moves at 1.68 ✕...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An ionized oxygen molecule (O2+) at point a has a charge +e and moves at 2.00...

    An ionized oxygen molecule (O2+) at point a has a charge +e and moves at 2.00 x 10^3 m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop a point B, a distance of 0.750 mm past A on the x-axis. Calculate (a) the x-component of the electric field and (b) the potential difference between points A and B.

  • 9. An ionized oxygen molecule (O2) at point A has charge t and moves at 2.00...

    9. An ionized oxygen molecule (O2) at point A has charge t and moves at 2.00 x 103 m/s in the positive x-direction. A constant electric force in the negative x-direction slows the molecule to a stop at point B, a distance of 0.750 mm pastA on the x-axis. Calculate (a) the x-component of the electric field and (b) the potential difference between points A and B.

  • A point charge q = +39.0 µC moves from A to B separated by a distance...

    A point charge q = +39.0 µC moves from A to B separated by a distance d = 0.184 m in the presence of an external electric field E with arrow of magnitude 295 N/C directed toward the right as in the following figure. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) Find the electric force exerted on...

  • A point charge q = +41.0 µC moves from A to B separated by a distance...

    A point charge q = +41.0 µC moves from A to B separated by a distance d = 0.167 m in the presence of an external electric field E with arrow of magnitude 265 N/C directed toward the right as in the following figure. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) Find the electric force exerted on...

  • A particle has a charge of +2.6 ?C and moves from point A to point B,...

    A particle has a charge of +2.6 ?C and moves from point A to point B, a distance of 0.23 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +8.1 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the...

  • A particle has a charge of +2.8 μC and moves from point A to point B,...

    A particle has a charge of +2.8 μC and moves from point A to point B, a distance of 0.26 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +7.8 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the...

  • A particle has a charge of +3.4 μC and moves from point A to point B,...

    A particle has a charge of +3.4 μC and moves from point A to point B, a distance of 0.11 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +9.4 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the...

  • A particle has a charge of +3.4 μC and moves from point A to point B,...

    A particle has a charge of +3.4 μC and moves from point A to point B, a distance of 0.26 m. The particle experiences a constant electric force, and its motion is along the line of action of the force. The difference between the particle's electric potential energy at A and B is EPEA - EPEB = +7.9 x 10-4 J. (a) Find the magnitude of the electric force that acts on the particle. (b) Find the magnitude of the...

  • 1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗  directed...

    1. A particle with a charge of +4.20 nC is in a uniform electric field E⃗  directed to the negative x direction. It is released from rest, and after it has moved 6.00 cm , its kinetic energy is found to be 1.50×10−6 J . a. What work was done by the electric force? b. What was the change in electric potential over the distance that the charge moved? c. What is the magnitude of E? d. What was the change...

  • A uniform electric field has magnitude E and is directed in the negative x-direction.

    A uniform electric field has magnitude E and is directed in the negative x-direction. The potential difference between point a (at x = 0.60 m) and point b (at x = 0.80 m) is 240 V. (CLO2-PLO2, C2) (a) Which point, a or b, is at the higher potential? (b) Calculate the value of E. (c) A negative point charge q = -0.500 mC is moved from b to a. Calculate the work done on the point charge by the electric field. 

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT