A child with a mass of 29.4 kg sits in a sled at the top of a hill that is 13.7 m high. Assuming no energy is lost to friction as the child slides down hill, what is the child's kinetic energy at the bottom of the hill?
a. 3.50e+3J
b. 2.40e+3J
c. 2.63e+3J
d. 3.95e+3J
e. 2.98e+3J
Since no energy is lost to fraction.
So using conservation of the energy
Kinetic energy = change in the potential energy
K=mgH
here m=29.4kg H=13.7 m , g=9.81 m/s^2
K=29.4×9.81×13.7
K=3951.2718 J
K=~3.95×10^3 J
so correct answer is (d) .
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