A simple random sample of 16 observations is derived from a normally distributed population with a known standard deviation of 2.5. [You may find it useful to reference the z table.]
a. Is the condition that X− is normally distributed satisfied? Yes No
b. Compute the margin of error with 95% confidence. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answer to 2 decimal places.)
c. Compute the margin of error with 90% confidence. (Round intermediate calculations to at least 4 decimal places. Round "z" value to 3 decimal places and final answer to 2 decimal places.)
d. Which of the two margins of error will lead to a wider interval?
The margin of error with 90% confidence.
The margin of error with 95% confidence.
Since n = 16 < 30 but population standard deviation is known thus, X follows normal distribution
b) n = 16
= 2.5
margin of error with 95% confidence = (Z
/2)(
/
)
= (1.96)(2.5/
)
= (1.96)(2.5/4)
= 4.9/4
= 1.225
c) Margin of error with 90% confidence =
(Z
/2)(
/
)
= (1.65)(2.5/
)
= 4.125/4
= 1.03125
d) The margin of error with 95% confidence will lead to wider interval.
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