for the rxn
1-pentene + I2-THF-NaBH4-Peroxides -> 1-pentanol
How does the reaction and the equilibrium of the I2-THF-NaBH4 reaction influence it's reactivity towards a terminal alkene
for the rxn 1-pentene + I2-THF-NaBH4-Peroxides -> 1-pentanol How does the reaction and the equilibrium of...
please keep simple
for the rxn 1-pentene 12-THF-NaBH4-Peroxides -> 1-pentanol How does the reaction and the equilibrium of the 12- THF-NaBH4 reaction influence it's reactivity towards a terminal alkene
For this rxn: 1-hexene, I2, THF, NaBH4 -> 1-hexanol How does the reaction and the equilibrium of the I2-THF-NaBH4 reaction influence it's reactivity towards a terminal alkene
1) At 298 K, an equilibrium
mixture contains P H2=0.958 atm, P I2= 0.877 atm and P HI=0.020
atm. Please try and answer all!
You must show all your work to receive credit. Watch sig figs! Consider the reaction: 1) At 298 K, an equilibrium mixture contains P H2-0.958 atm, P ½=0.877 atm, and P HI-0.020 atm. Calculate the value of the equilibrium constant Kp? a) (o, o2) 0.938x o.87? b) And what is the value of the equilibrium constant...
1a. How does a catalyst change the equilibrium of a
reaction?
r
A catalyst lowers the activation energy and so changes the rate
constants and therefore changes the equilibrium constant.
A catalyst lowers the activation energy and so changes the rate
constants and therefore changes the equilibrium constant.
A catalyst helps to form more products so it always increases
the equilibrium constant.
A catalyst adds a reactant to the equilibrium expression and so
changes the equilibrium constant.
A catalyst doesn't...