Suppose John and his wife know that the probability of one of their children having blue eyes is 20%. If John and his wife have 5 children, what is the probability that less than 3 children will have blue eyes?
Round your answer to 4 decimal places.
Given that ,
p = 0.20
1 - p = 1 - 0.20= 0.80
n = 5
Using binomial probability formula ,
P(X = x) = (n C x) * px * (1 - p)n - x
P(X <3 ) = P(X=0) +P(X=1)+P(X=2)
= (5 C 0) *0.200 * (0.80)2+(5 C 1) *0.201 * (0.80)4+(5 C 2) *0.202 * (0.80)3
probability =0.9421
Suppose John and his wife know that the probability of one of their children having blue...
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