I was having trouble figuring out this problem. I used the loop method, but I got...
I was having trouble figuring out this problem. I used the loop method, but I got 5.67 A instead of -57.0 A for Current #1, which is the correct answer.
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A sick car battery with an emf of 11.4 V and an internal resistance of 0.01 Ω is connected to a load of 2.0 Ω. To help the ailing battery, a second battery with an emf of 12.6 V and an internal resistance of 0.01 Ω is connected by jumper cables to the terminals of the first battery. (a) Draw a diagram of this circuit. (b) Find the current in each part of the circuit. (c) Find the power delivered by the second battery and discuss where this power goes, assuming that the emfs and internal resistances of both batteries remain constant.
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I was having trouble figuring out this problem. I used the loop
method, but I got...
An old car battery that has an emf of elementof_1 = 11.6 V and an internal...
An old car battery that has an emf of elementof_1 = 11.6 V and an internal resistance of 40.0 mohm is connected to an R = 2.00 ohm resistor. In an attempt to recharge the battery, you connect a second battery that has an emf of elementof_2 = 12.6 V and an internal resistance of 10.0 mohm in parallel with the first battery and the resistor with a pair of jumper cables. Draw a diagram of the circuit. Choose File...
1)A battery having an e.m.f. of 105 V and an internal resistance of 1 Ω is...
1)A battery having an e.m.f. of 105 V and an internal resistance of 1 Ω is connected in parallel with a d.c. generator of e.m.f. 110 V and internal resistance of 0.5 Ω to supply a load having a resistance of 8 Ω. Calculate: (a) the currents in the battery, the generator and the load; (b) the potential difference across the load. 1)b.Two batteries are connected in parallel. The e.m.f. and internal resistance of one battery are 120 V and...
A circuit consisting of 5 resistors is shown in the graph
A circuit consisting of 5 resistors is shown in the graph. Their resistances are R1 = 18 Ω, R2 = 75 Ω, R3=98Ω,R4 = 27 Ω, and R5 = 36 Ω, and the emf of the battery is ε=5.5 V. Suppose the internal resistance of the battery is zero. Part (a) Express the equivalent resistance of the combination of R2, R3, and R4. Part (b) Express the total resistance of the circuit R in terms of R1, R2, R3,R4. and R5. Part (c)...
A circuit is constructed with five resistors and one real battery as shown above right. We...
A circuit is constructed with
five resistors and one real battery as shown above right. We model.
The real battery as an ideal emf V = 12 V in series with an
internal resistance r as shown above left. The values for the
resistors are: R1 = R3 = 22 Ω, R4 = R5 = 82 Ω and R2 = 147 Ω. The
measured voltage across the terminals of the batery is Vbattery =
11.6 V.
A circuit is constructed...
Problem 1 R=10012 E15 VI C=60 F R=20012 C-40F R-150K In the figure above, two capacitors...
Problem 1 R=10012 E15 VI C=60 F R=20012 C-40F R-150K In the figure above, two capacitors and three resistors are connected to a 15 V battery as shown. At t=0, switch S is closed. What is the (a) equivalent capacitance, (b) equivalent resistance and (c) time constant of the circuit. At t=5.0 s, calculate (d) the current through the battery, and (e) charge on C. Problem 2 Consider the following circuit, 3 batteries with EMF: E1 = 6 V, E2...
Constants Now we will tackle a more complex two-loop circuit using Kirchhoff's rules. In the circuit...
Constants Now we will tackle a more complex two-loop circuit using Kirchhoff's rules. In the circuit shown in (Figure 1), a 12 V power supply with unknown resistance r (represented as a battery) is connected to a run-down rechargeable battery with unknown emf e and internal resistance 1 and to a bulb with resistance 3 2 The current through the bulb is 2 A, and the current in the run- down battery is 1 A; the directions of both of...
1- Capacitor B has half of the capacitor A. Compare the load of capacitor A with...
1- Capacitor B has half of the capacitor A. Compare the load of capacitor A with capacitor B charge when the two capacitors remain connected in series with a battery for a long time. 2- A capacitor immersed in the air has capacitance equal to 12.5 μF when the potential difference at its terminals is 24.0V. If we insert a constant material dielectric equal to 3.75 between the capacitor plates, filling the space between them completely, (a) how much energy...
I am getting the last one wrong and I don't know why. Help with the 3rd...
I am getting the last one wrong and I don't know why.
Help with the 3rd question please.
Мар hile studying a coil of unknown inductance, you connect it in series with an ideal 25.0 V battery and a 1.50 x 102 Q resistor. You then place an oscilloscope across one of these circuit elements and use the oscilloscope to measure the voltage across the circuit element as a function of time. The result is shown in the figure Across...
1. When the current in a toroidal solenoid is changing at a rate of 0.0270 A/s...
1. When the current in a toroidal solenoid is changing at a rate of 0.0270 A/s , the magnitude of the induced emf is 12.6 mV . When the current equals 1.40 A , the average flux through each turn of the solenoid is 0.00320 Wb .How many turns does the solenoid have? 2. You need a transformer that will draw 33 W of power from a 220 V (rms) power line, stepping the voltage down to 12 V (rms)....
7-11 please 7. Two parallel conducting plates are connected to a constant voltage source. The magnitude...
7-11 please
7. Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plates is 2,000 N/C. If the voltage is halved and the distance between the plates is reduced to 1/4 the original distance, the magnitude of the new electric field is (A) 8000 N/C (B) 1,600 N/C (C) 2,400 N/C (D) 4,000 N/C (E) 10,000 N/C 8. A parallel-plate capacitor is charged by connection to a battery. If the...
An old car battery that has an emf of elementof_1 = 11.6 V and an internal resistance of 40.0 mohm is connected to an R = 2.00 ohm resistor. In an attempt to recharge the battery, you connect a second battery that has an emf of elementof_2 = 12.6 V and an internal resistance of 10.0 mohm in parallel with the first battery and the resistor with a pair of jumper cables. Draw a diagram of the circuit. Choose File...
A circuit is constructed with
five resistors and one real battery as shown above right. We model.
The real battery as an ideal emf V = 12 V in series with an
internal resistance r as shown above left. The values for the
resistors are: R1 = R3 = 22 Ω, R4 = R5 = 82 Ω and R2 = 147 Ω. The
measured voltage across the terminals of the batery is Vbattery =
11.6 V.
A circuit is constructed...
Problem 1 R=10012 E15 VI C=60 F R=20012 C-40F R-150K In the figure above, two capacitors and three resistors are connected to a 15 V battery as shown. At t=0, switch S is closed. What is the (a) equivalent capacitance, (b) equivalent resistance and (c) time constant of the circuit. At t=5.0 s, calculate (d) the current through the battery, and (e) charge on C. Problem 2 Consider the following circuit, 3 batteries with EMF: E1 = 6 V, E2...
Constants Now we will tackle a more complex two-loop circuit using Kirchhoff's rules. In the circuit shown in (Figure 1), a 12 V power supply with unknown resistance r (represented as a battery) is connected to a run-down rechargeable battery with unknown emf e and internal resistance 1 and to a bulb with resistance 3 2 The current through the bulb is 2 A, and the current in the run- down battery is 1 A; the directions of both of...
I am getting the last one wrong and I don't know why.
Help with the 3rd question please.
Мар hile studying a coil of unknown inductance, you connect it in series with an ideal 25.0 V battery and a 1.50 x 102 Q resistor. You then place an oscilloscope across one of these circuit elements and use the oscilloscope to measure the voltage across the circuit element as a function of time. The result is shown in the figure Across...
7-11 please
7. Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plates is 2,000 N/C. If the voltage is halved and the distance between the plates is reduced to 1/4 the original distance, the magnitude of the new electric field is (A) 8000 N/C (B) 1,600 N/C (C) 2,400 N/C (D) 4,000 N/C (E) 10,000 N/C 8. A parallel-plate capacitor is charged by connection to a battery. If the...
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