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A father fashions a swing for his children out of a long rope that he fastens...

A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 6.40 m long, his tangential speed at the bottom of the swing is 7.45 m/s. What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing?

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Answer #1

When an object moving in a circular motion of radius R with speed v, the acceleration of the object is

The acceleration is due to change in direction of the velocity of object, and it is called centripetal acceleration.

In this question a child undergoes a motion in a circular arc centered at the point where the rope is fastened. The radius of the arc is approximately the length rope. The speed at the bottom is v=7.45m/s, so the centripetal acceleration is

The force points in the upward direction along the rope. The centripetal force is provided by the net force of tension in the rope and the weight of the child.

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