A force of 85.5 N in the horizontal direction is required to set a 25.4-kg box,...
A force of 85.5 N in the horizontal direction is required to set a 25.4-kg box, initially at rest on a flat surface, in motion. After the box begins to move, a horizontal force of 55.5 N is required to maintain a constant speed.
(a) What is the coefficient of static friction between the box
and the surface?
(b) What is the coefficient of kinetic friction between the box and
the surface?
Homework Answers
here,
the mass of box , m = 25.4 kg
a)
let the coefficient of static friction between the box and the surface be us
the force required to set the box in motion , ffs = us * m * g
85.5 = us * 25.4 * 9.81
solving for us
us = 0.343
the coefficient of static friction between the box and the surface is 0.343
b)
let the coefficient of kinetic friction between the box and the surface be uk
the force required to keep the box in motion , ffk = uk * m * g
55.5 = uk * 25.4 * 9.81
solving for uk
uk = 0.22
the coefficient of static friction between the box and the surface is 0.22
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