Question

Calculations:

	sales(y)	calls(x1	time (x2)	years (x3)
Min	40	69	28.113208	1
Q1	45	87.5	33.756166	2
Median	51.5	105.5	36.858333	4
Q3	58	118.25	41.440757	5
Max	60	137	49.538462	6

D) Mean time per call is greater than 15 minutes Ho=15 Ha>15 Bar x =15,t=1.96,s=5.099,n=100 15(+/-)(1.96)(5.099/sq.rt.100)=0.994 C.I.=(14,16) 37.6=mean 5.099=standard deviation so t=37.6-15/5.099/10=43.10 t value =43.10 Tdist(43,15.99,1= 2.6312e-66 (really small ) thus we would reject null. (this is less than .05 so I reject null.) F-test=196

Answer 1