Question

In your script file perform the following calculations

: - Prompt the user to enter in a year.

- Use a nested if statement to determine if the year is a leap year by checking the following rules:

1. If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.

2. If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.

3. If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.

4. The year is a leap year.

5. The year is not a leap year.

- Depending on the result, print out the appropriate messages where xxx is the year o 'xx is a leap year and has 366 days' or 'xx is not leap year and has 365 days'

- NOTE: to check if a number is divisible by 4, you can check if the rounded number/4 is equal to the number/4

Answer 1

#source code in c langauge:

#include <stdio.h>

int main() {

int year;

printf("enter a year:");

scanf("%d",&year);

if (year%4==0) {

if(year%100==0) {

if(year% 400 == 0){

printf("%d is a leap year and has 366 days",year);

}

else{

printf("%d is not a leap year and has a 365 days",year);

}

}

else{

printf("%d is a leap year and has 366 days",year);

}

}

else{

printf("%d is not a leap year and has 365 days",year);

}

printf("\n");

return 0;

}

#output:

#source code in matlab:

year=input("enter a year:")
if (mod(year,4)==0)
if(mod(year,100)==0)
if(mod(year,400) == 0)
sprintf("%d is a leap year and has 366 days",year)
else
sprintf("%d is not a leap year and has a 365 days",year)
end
  
else
sprintf("%d is a leap year and has 366 days",year)
end
else
sprintf("%d is not a leap year and has 365 days",year)
end

#output:

#if you need any other language or more information needed comment below..