Assume that adults have IQ scores that are normally distributed with a mean of
mu equals 100μ=100
and a standard deviation
sigma equals 20σ=20.
Find the probability that a randomly selected adult has an IQ between
8484
and
116116.
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The probability that a randomly selected adult has an IQ between
8484
and
116116
is
nothing.
(Type an integer or decimal rounded to four decimal places as needed.)
solution
P(84< x < 116) = P[(84-100) /20 < (x -
) /
< (116-100) / 20)]
= P( -0.8< Z < 0.8)
= P(Z <0.8 ) - P(Z <-0.8)
Using z table
= 0.7881-0.2119
probability= 0.5762
Assume that adults have IQ scores that are normally distributed with a mean of mu equals...
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