Question

Suppose that a principal of a local high school tracks the number of minutes his students...

Suppose that a principal of a local high school tracks the number of minutes his students spend texting on a given school day. He finds that the distribution of minutes spent texting is roughly normal with a mean of 60 and a standard deviation of 20. Use this information to answer the question.

1. Based on the statistics, what is the probability of selecting at random a student who spends between 10 and 30 minutes texting?

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Answer #1

Solution :

Given that ,

mean = = 60

standard deviation = = 20   

P(10< x < 30) = P[(10-60) /20 < (x - ) / < (30-60) /20 )]

= P(-2.5 < Z <-1.5 )

= P(Z <-1.5 ) - P(Z < -2.5)

Using z table   

= 0.0668-0.0062

probability= 0.0606

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