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For the reaction shown in question 21(a), if you begin with 16.0 g of K2PtCl4, what...

For the reaction shown in question 21(a), if you begin with 16.0 g of K2PtCl4, what mass of ammonia (NH3) should be used to completely react with the K2PtCl4? Molar mass of K2PtCl4 = 415.1 g mol-1 Molar mass of NH3 = 17.03 g mol-1

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