In a study of the formation of NOx air pollution, a chamber heated to 2200°C was filled with air (0.790 atm N2, 0.210 atm O2). What are the equilibrium partial pressures of N2, O2, and NO if Kp = 0.0460 for the following reaction:
N2+O2 (equilibrium arrow) N2O2
Part 1
P(N2) = atm
Part 2
P(O2) = atm
Part 3
P(NO) = atm
N2 + O2 -----------> 2NO , Kp = 0.046
0.79 0.21 0 (at t=0)
0.79-x 0.21-x 2x (at t=equilibrium)
Kp = (2x)^2 / (0.79-x)*(0.21-x)
0.046 (0.79-x) (0.21-x) = 4x^2
0.046 (x^2 - x + 0.1659) = 4x^2
0.046x^2 - 0.046x + 0.0076314 = 4x^2
3.954x^2 + 0.046x - 0.0076314 = 0
After solving above equation, we get
x = 0.0385
So, P(NO) = 2x = 2*0.0385 = 0.077 atm
P(N2) = 0.79-x = 0.79 - 0.0385 = 0.7515 atm
P(O2) = 0.21 - x = 0.21 - 0.0385 = 0.1715 atm ..
. ANSWER
In a study of the formation of NOx air pollution, a chamber heated to 2200°C was...
In a study of the formation of NOx air pollution, a chamber heated to 2200°C was filled with air (0.790 atm N2, 0.210 atm O2). What are the equilibrium partial pressures of N2, O2, and NO if Kp = 0.0490 for the following reaction: N2(g) + O2(g) <---> 2 NO(g)
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4.
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Torr)
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