During basketball practice, Robert makes 5 free-throw attempts. If the probability that he gets a basket...
During basketball practice, Robert makes 5 free-throw attempts. If the probability that he gets a basket on any one free throw is 60%, independent of the other attempts, what is the probability that he makes at least 1 basket out of 5 attempts?
Homework Answers
p = 0.6
q = 1 - 0.6 = 0.4
P(at least 1 basket out of 5) = 1 - P(no basket) = 1 - 0.4^5 = 0.98976
Hence, 0.98976 is the probability that he makes at least 1 basket out of 5 attempt.
If it ask for 4 decimal places then answer is 0.9898
Please comment if any doubt. Thank you.
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