1. What is the mass in mg of 1.60 mmol of acetanilide? (Show your work)
Answer:
We'll use formula-
~ no. of moles =
or rearranging this we get,
mass = no. of moles × molar mass
1) calculating no. of moles -
we have 1.60 mmoles of acetanilide
1 mole = 1000 mmols
1mmol =
1.60mmol =
= 0.0016 moles
2) Calculating molar mass-
chemical formula of acetanilide = C8H9NO
So, molar mass = (12×8) + (1×9) + (14) + (16)
= 135 g/moles
3) Applying formula:
mass = molar mass × no. of moles
= (135 × 0.0016) grams
= 0.216 grams
or 1g = 1000 mg
0.216g = (0.216 × 1000) mg
= 216 mg
1. What is the mass in mg of 1.60 mmol of acetanilide? (Show your work)
Show work please!!!
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show your calculations.
2. Use 3g of 3-nitrophthalic acid and the new equivalent values
to determine what quantities of reactants and solvents are needed
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2
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Assume that your original sample of acetanilide was 80% pure. What is the maximum amount of pure acetanilide that you could recover after recrystallization? weight of crude acetanilide from the experiment is 0.513g weight of pure acetanilide from the experiment is 0.365g % Recovery from the experiment is 71.15%
please complete both tables and show your calculations
thanks
mass of the product 2.419 g
Équivalent MW(8/mol) Density(g/cm2) Mass (g or ml) 6.6 g mmol Réactants 50 1.02 130.14 Ethyl Acetoacetate 0.38g 1.93 g 12.5 0.88 30.03 paraformaldehyde 25 1.17 77.08 Ammonium acetate 25 ml 18 water Result table Theoretical Experimental Percentage Theoretical MW yield (mmol) yield (mg) yield ( mg ou 253.29 Product ННо O paraformaldehyde NH2OAC EtO OEt H2O A Scheme 3. Hantzsch Ester synthesis under ac