In a normal distribution with µ = $19,000 and the Interquartile range is $5000 (IQR=5000), find...
In a normal distribution with µ = $19,000 and the Interquartile range is $5000 (IQR=5000), find Q1.
Homework Answers
Answer)
In normal distribution
Q1 = mean - 0.67*s.d..... EQUATION 1
Q3 = mean + 0.67*s.d.... EQUATION 2
Iqr = Q3 - Q1 = 5000
Subtracting equation 1 from 2
We get,
Q3 - Q1 = 1.34*s.d
5000 = 1.34*s.d {as Q3 - Q1 = 5000}
S.d = 3731.34328358
So, Q1 = 19000 - 0.67*3731.34328358 = 16500
Answer is 16500
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