Which of the following is possible if a particle maintains a nonzero constant acceleration? Answer is: A particle moves in the positive direction for awhile and then moves in the negative direction. Please explain!
Which of the following is possible if a particle maintains a nonzero constant acceleration? Answer is:...
Please readable.
2) For a moving particle which has a constant acceleration, is it possible to reverse its direction of motion? Explain the reason of your answer briefly.
Rotational motion with a constant nonzero acceleration is not uncommon in the world around us. For instance, many machines have spinning parts. When the machine is turned on or off, the spinning parts tend to change the rate of their rotation with virtually constant angular acceleration. Many introductory problems in rotational kinematics involve motion of a particle with constant, nonzero angular acceleration. The kinematic equations for such motion can be written as and . Here, the symbols are defined as...
If the velocity of a particle is nonzero, can the particle's acceleration be zero? O yes no Explain This answer has not been graded yet. Need Help?Read It If the velocity of a particle is zero, can the particle's acceleration be zero? O yes O no Explain This answer has not been graded yet. Need Help? L Reade」
If you move at a constant, positive acceleration and your velocity is in the negative direction, then the magnitude of your velocity is: A. Is also constant, but nonzero. B. Is zero. C. Is increasing. D. Is decreasing.
The figure gives the acceleration of a 4.0 kg particle as an applied force moves it from rest along an x axis from x = 0 to x = 9.0 m. The scale of the figure's vertical axis is set by a_s = 10.0 m/s^2. How much work has the force done on the particle when the particle reaches (a) x = 4.0 m, (b) x = 7.0 m, and (c) x = 9.0 m? What is the particle's speed...
Problem 2: A particle is traveling with uniform (constant) speed, v. Answer the following questions carefully a. If the particle is traveling along a straight line path, with this constant speed, what is the magnitude of its acceleration vector? What is the direction of the acceleration vector? b. If the particle is traveling along a circular path of radius of curvature, p. what is the magnitude of the acceleration vector? What is the direction of the acceleration vector? Why is...
At t = 0, a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0i - 4.0j)m/s2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle? 10 m/s 16 m/s 12 m/s 14 m/s 26 m/s
At which of the six number points does the particle have no
(zero) acceleration?
At which of the six number points does the particle have the
greatest displacement if it started from x = 0 at
t = 0?
At which of the six number points does the particle have the
smallest displacement if it started from x = 0 at
t = 0?
If the particle started from x = 0 at t = 0,
is its postion, x...
In the figure, particle A moves along the line y = 33 m with a constant velocity v→ of magnitude 3.5 m/s and directed parallel to the x axis. At the instant particle A passes the y axis, particle B leaves the origin with zero initial speed and constant acceleration a→ of magnitude 0.46 m/s2. What angle θ between a→ and the positive direction of the y axis would result in a collision?
please i need help asap Problem 1 The acceleration of a particle moving only on a horizontal xy plane is given by a=3ti+4tj, where a is in meters per seconds squared and t is in seconds, at t=0, the position vector r=(20.0m)i+(40.0m)j locates the particles, which then has the velocity vector v=(5.00m/s)i+(2.00m's)j. at t=4.00s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?...