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A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150...

A 400 kg bomb sitting at rest on a table explodes into three pieces. A 150 kg piece moves off to the East with a velocity of 150 m/s. A 100 kg piece moves off with a velocity of 200 m/s. What is the velocity of the third piece?

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Answer #1

using conservation of momentum

initial momentum of system= final momentum of system

M v = m1 v1 +m2v2 + m3 v3

0 = 150* 150 + 100* 200 + (400 - 150 - 100) v3

v3 = 283.33 m/s

directed to the west

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Comment before rate in case any doubt, will reply for sure.. goodluck

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