Given a 200 Amp common current and an impedance of 2+j4, calculate the power loss.

Question

Question

engineering Electrical-Engineering

Answer 1

Answer #1

By using formula for power loss or power absorbed or power consumed or real power we get the solution.

Answer 2

Similar Homework Help Questions

can I have the correct solutions, answers are given impedance of (2 + j4)n per phase,...

can I have the correct solutions, answers are given impedance of (2 + j4)n per phase, feeds two balanced 2.7 A three-phase line, which has an three-phase loads that are connected in parallel. One of the loads is Y-connected with an impedance of (30 + (60 - impedance of j40)N per phase, and the other is A-connected with an j45) per phase. The line is energized at the sending end from a 60-Hz, three-phase, balanced voltage source of 120V3 V...
Find the current through the impedance of 3+j4 and change the circuit at the terminals A...

Find the current through the impedance of 3+j4 and change the circuit at the terminals A and B by the Thevenin circuit Answers Z=2.50+j2.50 V= -50+j50 I= 0.69+j8.27 قلم کی o solo مرگ
A three-phase line, which has an impedance of (2 + j4) Ω per phase, feeds two...

A three-phase line, which has an impedance of (2 + j4) Ω per phase, feeds two balanced three-phase loads that are connected in parallel. One of the loads is Y- connected with an impedance of (30 + j40) Ω per phase, and the other is delta- connected with an impedance of (60 + j45) Ω per phase. The line is energized at the sending end from a 60-Hz, three phase, balanced voltage source of 120√3 V (rms, line- to-line). Determine...

Calculate the apparent power in kVA for a 200 amp, 120/208 volt, 3-phase service. Select one:...

Calculate the apparent power in kVA for a 200 amp, 120/208 volt, 3-phase service. Select one: a. 769 kVA b. 72 kVA c. 576 kVA d. 432 kVA
In practical voltage-source circuits, the load impedance can be too small, forcing the op-amp into current...

In practical voltage-source circuits, the load impedance can be too small, forcing the op-amp into current limiting with resulting distortion. Are there similar limits in the current-source circuits?
Given: Z1 = 4-j1.5 ohms; Z2 = 2+j4 ohms; Z3 = 2 ohms; 24 = 3...

Given: Z1 = 4-j1.5 ohms; Z2 = 2+j4 ohms; Z3 = 2 ohms; 24 = 3 + j5 ohms. If the four impedances are connected in parallel, find the magnitude of equivalent impedance in ohms. (No need to include the phase angle, ONLY THE MAGNITUDE)

A. For the system given in Figure A, find ) The equivalent impedance (Z) 2) The...

A. For the system given in Figure A, find ) The equivalent impedance (Z) 2) The current through the components (. 3) The power factor at the source end XFion X10 X100 72000 V X30 Figure A B. Draw the single-line equivalent of the given three phase system shown in Figure B 230v 2100 200 23012 2302akV
Calculate the complex power of the equivalent impedance of the following circuit, if the value of...

Calculate the complex power of the equivalent impedance of the following circuit, if the value of the current source A has a value of 2.3 A. Write the value of the apparent power in the solution, the angle will be verified in the procedure. A cos(25t +30°) 40 800mH 4mF
Problem 2 Assume the impedance of a circuit element is Z (3 +j4) 2. Determine the...

Problem 2 Assume the impedance of a circuit element is Z (3 +j4) 2. Determine the circuit element's conductance and susceptance. - 120 m A. G s, B = jl 60 mS B. G 333 mS, B-j250 mS C. G = 108 ms. B =-j 194 ms D. G-160 mS, B-j108 mS E. G 120 mS, B-j160 mS F. None of the other answers is correct.

Calculate the total impedance in the following circuit between point A and point B 2 Ohm...

Calculate the total impedance in the following circuit between point A and point B 2 Ohm -j4 Ohms j2 Ohms R3 4 Ohms 2 Ohms j6 Ohms