1. A. What is the best coefficient of performance for a refrigerator that cools an environment at −26.0°C and has heat transfer to another environment at 49.0°C?
B. How much work in joules must be done for a heat transfer of 4186 kJ from the cold environment?
C. What is the cost (in cents) of doing this if the work costs 13.0 cents per 3.60 ✕ 106 J (a kilowatt-hour)?
D. How many kJ of heat transfer occurs into the warm environment?
E. Discuss what type of refrigerator might operate between these temperatures.
1. A. What is the best coefficient of performance for a refrigerator that cools an environment...
(a) What is the best coefficient of performance for a refrigerator that cools an environment at -29.5°C and has heat transfer to another environment at 45.5°C? (b) How much work in joules must be done for a heat transfer of 4186 kJ from the cold environment? (c) What is the cost (in cents) of doing this if the work costs 15.0 cents per 3.60 x 106 J (a kilowatt-hour)? (d) How many kJ of heat transfer occurs into the warm...
a.) What is the best possible coefficient of performance for a refrigerator that cools an environment at -33.0 °C and exhausts heat to another environment at 39.0 °C? b.) How much work in joules must be done for a heat transfer of 3.925 × 106 J from the cold environment? c.)What is the cost of doing this, if the work costs 17.5 cents per 3.60 × 106 J (a kilowatt-hour)? d.) How many joules of heat transfer occurs into the...
Goal Solve for the performance coefficient of a refrigerator using a five- step process the includes: 1. Making a state table. 2. Making a process table. 3. Calculating the totals for Work, Heat, and Internal-Energy-Change. 4. Identifying the heat input (cold reservoir) and output (hot reservoir). 5. Calculating the performance coefficient of the refrigerator. isothermal Problem Shown in the figure to the right is a cyclic process undergone by a refrigerator. Your refrigerator shall use 8.0 moles of helium gas...
What is the Coefficient of Performance of a refrigerator is if is in an environment of 6860 J and is pumping down to a heat of 5893 J? Answer 0,071 Try another question like this one Finish - Type here to search e s esc # & 2 . ® N
TIUVICU TU. A refrigerator has a coefficient of performance of K = 2.1. Each cycle, it absorbs 3.75x104 J of heat from the cold reservoir. The refrigerator is driven by a Carnot engine that has an efficiency of e=0.5 Eckboard - The Cit x Bb Pre-Lab Assignments - 201 X C Six HepID=9ca21d320b455f2dffd7601af0f84482#10001 Part A How much mechanical energy is required each cycle to operate the refrigerator? Express your answer in joules to two significant figures. IVO ALDO a ?...
Problem 18.56 6 of 8 Review A refrigerator with a coefficient of performance of 1.85 absorbs 3.54x10* J of heat from the low- temperature reservoir during each cycle. Part A How much mechanical work is required to operate the refrigerator for a cycle? ΡΕΙ ΑΣφ + ? Submit Request Answer Part 8 How much heat does the refrigerator discard to the high-temperature reservoir during each cycle? 10 AED + + ? KJ Submit Request Answer
1. A food compartment is kept at -12°C by a refrigerator in an environment at 30° C. The total heat transfer to the food compartment is estimated to be 3300 kJ/hr and the heat rejection in the condenser is 4800 kJ/hr. Determine the power input to the compressor, in kW, and the COP of the refrigerator. 30°C 800 kJ/h in 3300 kJ/h -12°C
A freezer has a coefficient of performance of 6.30. It is
advertised as using 466 kWh/yr. Note: One kilowatt-hour
(kWh) is an amount of energy equal to running a 1-kW appliance for
one hour.
(a) On average, how much energy does it use in a single
day?
J
(b) On average, how much energy does it remove from the
refrigerator in a single day?
J
(c) What maximum mass of water at 22.8°C could the freezer freeze
in a single...
A refrigerator what we call a heat engine running backwards for the purpose of making a cool place cooler. Refrigerators/freezers/air conditioners extract heat from the cold reservoir (the refrigerator or home interior) and deposit it in the hot reservoir (the kitchen or outdoors). However, we take advantage of the same physics/engineering principles to build heat pumps which are heat engines running backwards for the purpose of making a warm place warmer. They extract heat from the cold reservoir (the outdoors)...
Solution (1) Fill in the State Table (all pressures in Pascals, all volumes in cubic meters, all temperatures in K). Pressure 100000 Volume 0.2 Temperature 300 100000 902.9 300000 0.2 902.9 du Work 40000 Heat 59.72 99.72 a- >b (2) Fill in the Process Table (all entries in Joules). -65900 O -65.9 X > c- 0 -59720 -59720 (3) Find the Totals: Work = -25900 Heat = -25900 dU = 0 X ] (4) Find the heat input (from "cold...