Calculate Moles of NaOH dispensed in three titrations with volumes 9.05 mL, 9.10 mL, 9.02 mL and molarity of NaOH at 0.1 M. Please show full work so I can understand where every calculation came from.
Calculate Moles of NaOH dispensed in three titrations with volumes 9.05 mL, 9.10 mL, 9.02 mL...
2. Calculate the molarity (M) of 30.0 g of NaOH in 350 mL of NaOH solution. Show all the step by step work: 3. Calculate the amount of solute, in moles, grams or milliliters, needed to prepare the following solutions. Show all the step by step solution: a. 1.00 L of a 3.00 M NaCl solution (moles of solute) b. 2.00 L of a 1.50 M NaOH solution (grams of solute) c. Milliliters of 1.50 M NaCl solution to obtain...
Laboratory Results Calculate the pH at each point of the titration and complete the table. (Show clearly your calculation procedures) I. Strong Acid/Strong Base Titrations (Addition of 0.1 M NaOH solution to 25 mL of 0.1 M HCl solution) Volume of NaOH added (ml) to 25 mL of 0.1 M HCI PH 12 | 17 22 25 27 29 31 33 50 (show your work for just any specific point of titration, e.g. at 22 mL)
Convert 15.6 mL of NaOH to moles Concentration of NaOH is 0.10 M NaOH molar mass = 39.997 g Please show all work. Thank you
calculate rad
Initial reading Volume NaOH added Calculation of Molar Concentration Moles KHC HẠO, 2.45 lb .60.40 m. 28.20 27.5027155 31.05 mL .5902 .6405 5863 oua 3 204.23 204.23 20423 3002889 .003136.281.00212 moi 002869003136 002871.0027 mol 28.20 87.50 27.55 31.05 1 01020 01140.1042.0879 m oloa Moles NaOH average , .006906 Volume NaOH added Molarity NaOH next page Average molarity NaOH Precision as RAD ppt F18 1.1020-1020/39/1 1140 - 1020 1.1042- + 1.0879-1020t
I’m so confused on how to do any of this.
Name Date General Chemistry I Lab CHE 1211 Data: Concentration of NaOH Trial Titration (to be used as practice) Initial burete eading4.0 ml Final burette reading 20.h m 22.om. Volume of NaOH used Repeat until 2 successful titrations are achieved. Titrations (to be used in calculations) K.Oml 0.bml 35.o mL 22.3 mL 38.5ml ↓ 30.6 mL45.0 mL 49.0 mL 35.5mL50.0 me 22.0mL H. m0 ml 1b.20 m 4.5ml Initial burette...
can someone please help me, this is a dry lab and im so lost
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Data Table Part I: Standardization of NaOH Trial One Trial Two 2.1245 3.2019 1.) Mass of empty weigh boat (9) 2.) Mass of weigh boat + solid KHP (9) 3.) Mass of solid KHP (9) Show calculation for Trial One: 8.56 19.85 4.) Initial volume of NaOH (mL) 5.) Final volume of NaOH (mL) 6.) Volume of NaOH used (ml) Show calculation for Trial One!...
I know, the answers but don’t
know how to show my work for the questions below, someone please
help!
Experiment 17A (43 of 127) Experiment 17A: Standardizing a Solution of Sodium Hydroxide Flask Trial 1 Trial 2 Initial Buret Reading, ml 0.00 mL 15.45 mL Final Buret Reading, mL 15.45 mL 30.00 mL 14.55ml Volume NaOH dispensed 15.45 ml Grams of KHP 0.785 g 0.736 g Moles of KHP Molar Mass of KHP = 204.23 g/mol 0.00384 0.00360 0.00360 0.247...
You perform a titration and obtain the following data. Calculate the molarity of the sodium hydroxide solution. Do not solve this problem with M1V1 = M2V2. Concentration of HC2H3O2: 0.120 M Volume of HC2H3O2 dispensed at the endpoint: 25.20 mL Volume of NaOH dispensed at the endpoint: 24.00mL Show formulas used an include all work please. Thanks.
Calculate the [HCL], [H3O+], pH, pOH and concentration of
[OH-].
Data Table: Molarity of Standardized NaOH RM Trial 1 Data Trail 2 Trial Volume of HCI 25 ml - 25mL NaOH, Initial buret reading, ml NaOH, Final buret reading ml Volume of NaOH used (ml) 22.55 ml 22.35m! 2256 x 1?L 22.35x10L Volume of NaOH used (L) Measured pH at endpoint Moles of NaOH 435x16?mos 4.31x102015 4.35x10 2 4.31X10 mos Moles of HCI Molarity of HCI 1724M 1.74M 1.732M Average...
65.0 mL of 0.125 M NaOH is titrated with 0.315 M HCl. What is the pH after the addition of 30.0 mL of HCl? Please show clear work and clarify where all numbers came from and equations used.