A college placement office conducted a survey of 100 engineers who had graduated from Stanford University....
A college placement office conducted a survey of 100 engineers who had graduated from Stanford University. For these engineers, the mean salary was computed to be $72,000 with a standard deviation of $8,000. The distribution of salary is roughly bell shaped.
If the distribution was not bell shaped, then what salary interval will contain 96.6% of the engineers?
Homework Answers
here since distribution was not bell shaped
number of standard deviation from mean that contain at least 96.6% of values
=sqrt(1/(1-0.966))
=5.4
therefore corresponding interval value =72000 -/+ 5.4*8000
=28800 to 115200
(please try 28640 to 115360 if above comes wrong due to rounding error)
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