It IS BELIEVED THAT 1/4 OF ADULTS OVER 50 YEARS OLD NEVER GRADUATE FROM HIGH SCHOOL. We WANT TO SEE IF THE PERCENTAGE IS THE SAME FOR 30 YEAR olds. How MANY Should WE SURVEY IN ORDER TO ESTIMATE THE PROPORTION OF NON-GRADS WITHIN 0.06 WITH 90% CONFIDENCE?
given data,
sample proportion is 50%
margin of error = 0.06
confidence level is 90%
sample size is
Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.1 is = 1.645
Sample Proportion = 0.25
ME = 0.06
n = ( 1.645 / 0.06 )^2 * 0.25*0.75
= 140.9388 ~ 141
It IS BELIEVED THAT 1/4 OF ADULTS OVER 50 YEARS OLD NEVER GRADUATE FROM HIGH SCHOOL....
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It is believed that as many as 25% of adults over 50 never graduated from high school. We wish to see if this percentage is the same among the 25 to 30 age group. How many of this younger age group must we survey in order to estimate the proportion of non-grads to within 6% with 90% confidence? Za = 1.645 2 Identify the following specific to the problem: a. What is p? b. What is 1 - p? c....
It's believed that as many as 22% of adults over 50 never graduated from high school. We wish to see if this percentage is the same among the 25 to 30 age group. Suppose we want to cut the margin of error to 6%.What is the necessary sample size?
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It's believed that as many as 22% of adults over 50 never graduated from high school. We wish to see if this percentage is the same among the 25 to 30 age group. b) Suppose we want to cut the margin of error to 4%. What is the necessary sample size?