A ray of light is incident on the surface of a transparent material shown below. The...
A ray of light is incident on the surface of a transparent material shown below. The angle of incident is θ1 = 45 deg. The index of refraction of air is n1 = 1. If the angle of refraction is θ2 = 35.7 deg, what is the index of refraction n2 of the material?
Homework Answers
Index of refraction of air = n1 = 1
Index of refraction of the material = n2
Angle of incidence = 
1 = 45o
Angle of refraction =
2 = 35.7o
By Snell's Law,
n1Sin1
= n2Sin2
(1)Sin(45) = n2Sin(35.7)
n2 = 1.21
Index of refraction of the material = 1.21
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