Find the 85% confidence interval and the margin of error using the following data show your work:
Sample Size: 50
Sample Mean: 83.172
Standard Deviation: 5.11
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Find the 85% confidence interval and the margin of error using the following data show your...
Find the margin of error for a 95% confidence interval for estimating the population mean when the sample standard deviation equals 92, with a sample size of (a) 400,(b) 1800. What is the effect of the sample size? 2. The margin of error for a 95% confidence interval with a sample size of 400 is (Round to the nearest tenth as needed.) b. The margin of error for a 90% confidence interval with a sample size of 1600 is (Round...
what is the margin of error and the confidence interval?
Question Help In a random sample of seven people, the mean driving distance to work was 24.7 miles and the standard deviation was 6.6 miles. Assuming the population is normally distributed and using the I-distribution, a 90% confidence interval for the population mean is (15.5, 33.9) (and the margin of error is 9.2). Through research, it has been found that the population standard deviation of driving distances to work is...
1. Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.0, 4.8) when estimating the mean height (in centimeters) of a sample of seedlings. 2. In a random sample of 26 people, the mean commute time to work was 32.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval for the...
To calculate a confidence interval, the margin of error (E) must first be calculated. The Margin of Error, E, for means is: E = 1.96*s/sqrt(n), where s is the sample standard deviation, n is the sample size. The “sqrt” stands for square root. The Margin of Error, E, for proportions is: E = 1.96*sqrt[p*(1-p)/n], where s is the sample standard deviation, n is the sample size, and p is the proportion. Use the Confidence Interval formula above, and the correct...
For confidence interval computations, if the sample size is increased, we expect the margin of error to: a. Increase b. Decrease c. stay the same The company you work for produces automotive parts for GM. A certain machine that makes a cutout in a piece of steel averages a cut size of 203.2085 mm with a standard deviation of 0.2083 mm. A random sample of 66 is taken from the population. What is the distribution of the sample mean? Approximately...
Using a T-Interval on your calculator to find a 95% confidence interval estimate of a mean when the sample mean from a sample of 35 individuals is 132.5 and the sample standard deviation is 14.7, what is the resulting margin of error?
Given the confidence interval for a mean of (74.5738,77.4262), from a sample of size 34 with a population standard deviation of σ=3.6, find the following: Margin of Error(ME)= Standard Error(SE)= Zc= what was the confidence level for this confidence interval?= (Show your work please)
Which of the following would produce a confidence interval with a larger margin of error than the 95% confidence interval with a sample size of 50? A. using a sample size of 100 and fix the confidence level. B. using a confidence level of 90% and fix the sample size. C. using a confidence level of 99% and fix the sample size. D. using a sample size of 500 and fix the confidence level. E. None of the above.
a.) The margin of error in a 95% confidence interval for the true mean of a population is 2.5, based on a random sample of 100 measurements. If the sample mean is 27.5, the 95% confidence interval must be b.) In a random sample of 100 measurements from a population with known standard deviation 200, the average was found to be 50. A 95% confidence interval for the true mean is c.) A.C. Neilsen reported that children between the ages...
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (4.1.5.3) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is The sample mean is