Question

shape.h

#pragma once
#include <iostream>
#include <string>
#include <cmath>
#include <climits>
#include <sstream>
#include <fstream>
#include <deque>
using namespace std;

class Shape {
public:
   Shape(string colorc);
   virtual ~Shape();
   string getColor(string getcolor);
   virtual void print() = 0;
private:
   string color;
};

shape.cpp

#include "Shape.h"
using namespace std;

Shape::Shape(string colorc) {
   color = colorc;
}
string Shape::getColor(string getcolor) {
   color = getcolor;
   return color;
}

this code does not compile because of

Shape::Shape(string colorc) {
   color = colorc;
}

i dont get why this is not compiling ive defined parameter on header file 'string colorc' and i am just calling the constructor when i write /**\ the code compiles

/*Shape::Shape(string colorc) {
   color = colorc;
}*/

help please thank you

Answer 1

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Answer:

Usually this error comes when you declare a virtual method but did not define . I have seen that in Shape class you defined Destructor as Virtual so you have to provide definition to it in Shape.h itself. There are two ways to solve it:

1) in Shape.h, provide definition of it as below:

virtual ~Shape() = 0;

After that code compiles.

2) Provide the definition in Shape.cpp as below:

Shape::~Shape(){
color =""; //anything will work for compilation
}