An irregularly-shaped iceberg has a volume of 3580 m3. It floats with 90% of its volume
underwater, in sea water with a density of 1025 kg/m3. The bottom of the iceberg hangs
18.5 m below the surface of the water.
a. What is the absolute pressure in the water at the bottom edge of the iceberg?
b. What is the density of the iceberg?
c. What is the mass of the iceberg?
(a) Pressure, Pabs = dwater*g*h + Po
Pabs = 1025*9.8*18.5 + 101325 = 185832.5 Pa + 101325 Pa
Pabs = 287157.5 Pa
(b) As the iceberg floats on sea water, the ratio of density incase of floatation is given as,
dice/dwater = Vimmersed/Vice
dice = 1025*90/100 = 922.5 Kg/m3
(c) Mass of iceberg, mice = dice*Volume = 922.5*3580
mice = 3302550 Kg = 3.3*106 Kg
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